if greatest angle of a parallelogram in 30 degree more than twice the smallest angle then find the greatest angle of the parallelogram

let the angle be x and other angle be 2x + 30.

we know that adjacent angles in a parallelogram form co-interior angles .

therefore, x + 2x +30 = 180

3x = 150, then x = 50 degree.

so the greatest angle is 2x + 30 = (2*50) + 30 = 100 + 30= 130 degree.

Hope it helped you.