If h=6.6*10^-34 js then deBroglie wavelength of particle having momentum = 3.3*10^-24 kgm/s
Dear student,
De Broglie wavelength = λ = h/p where h is the Planck's constant and p is the momentum.
So here λ = 6.6 x 10-34 / 3.3 x 10 -24 = 2 x 10-10 m = 2 A
Hope this helps.
Regards
De Broglie wavelength = λ = h/p where h is the Planck's constant and p is the momentum.
So here λ = 6.6 x 10-34 / 3.3 x 10 -24 = 2 x 10-10 m = 2 A
Hope this helps.
Regards