If log 2 (x+y) = log 3 (x-y)=log 25/log 0.2 find x and y Share with your friends Share 0 Avinash Garg answered this Dear Student we have log 2(x+y)=log 3(x-y)=log 25log 0.2take log 2(x+y)=log 25log 0.2⇒ log 2(x+y)=log(25-0.2)⇒x+y=24.82=12.4 --(1)take log 3(x-y)=log 25log 0.2=log(25-0.2)⇒x-y=24.83=8.27----(2)add (1) and (2); we get2x=12.4+8.27⇒x=20.672=10.34from (1); 10.34+y=12.4y=12.4-10.34=2.06 Regards 1 View Full Answer Aparna answered this log(x-y)-log(x+y)-formula log2(x+y)=log3(x-y) log2(x+y)=log3(x-y)=-2 solve them x=13/72 y=5/72 0