If log 2 (x+y) = log 3 (x-y)=log 25/log 0.2 find x and y

Dear Student

we have log 2(x+y)=log 3(x-y)=log 25log 0.2take  log 2(x+y)=log 25log 0.2 log 2(x+y)=log(25-0.2)x+y=24.82=12.4  --(1)take log 3(x-y)=log 25log 0.2=log(25-0.2)x-y=24.83=8.27----(2)add (1) and (2); we get2x=12.4+8.27x=20.672=10.34from (1); 10.34+y=12.4y=12.4-10.34=2.06

Regards

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log(x-y)-log(x+y)-formula
log2(x+y)=log3(x-y)
log2(x+y)=log3(x-y)=-2
solve them
x=13/72
y=5/72
 
  • 0
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