If log 2to the base 10=0.3010 Find value of log25 to the base 8

Dear Student, 
Consider 
log825=log81004              =log8100-log84   [logab=loga-logb]              =log8102-log84              =2log810-log84   [logbam=mlogba]              =2log10log8-log4log8   [logba=logalogb]              =2log23-log22log23   [log1010=1]              =23log2-2log23log2   [logbam=mlogba]              =231log2-1              =2310.3010-1  [since log102=0.3010]              =1.548
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