if one root of the equation (l-m)x^2 + lx +1 =0 be the double of the other and if l is real show that m<_9/8

Dear student
We have,(l-m)x2+lx+1=0Let the root of the above polynomial be r. Then according to question other root is double of the one root. So, the other root is 2rr+2r=-ll-m3r=-ll-mr=-l3l-m   ..(1)and r.2r=1l-m2r2=1l-mr2=12l-ml29l-m2=12l-m   (from 1)2l2=9l-m2l2-9l+9m=0For l to be real, the discriminant is non- negative818×9mm98Hence Proved
Regards

  • 36
What are you looking for?