if one root of the equation (l-m)x^2 + lx +1 =0 be the double of the other and if l is real show that m<_9/8 Share with your friends Share 9 Lovina Kansal answered this Dear student We have,(l-m)x2+lx+1=0Let the root of the above polynomial be r. Then according to question other root is double of the one root. So, the other root is 2rr+2r=-ll-m⇒3r=-ll-m⇒r=-l3l-m ..(1)and r.2r=1l-m⇒2r2=1l-m⇒r2=12l-m⇒l29l-m2=12l-m (from 1)⇒2l2=9l-m⇒2l2-9l+9m=0For l to be real, the discriminant is non- negative81≥8×9m⇒m≤98Hence Proved Regards 36 View Full Answer