if sin-1[ 2xy/1+y2] =b,where b is a constant ,then what is the value of dy /dx this question is - Maths - Continuity and Differentiability

Question

if sin-1​[ 2xy/1+y2​] =b,where b
is a constant ,then what is the value of dy /dx?
this question is in your study material topic test but i didn't
understand how 2y = 2(y sin b - x) dy/dx come?

Anuradha Sharma · Accepted Answer

Dear Student, sin-12xy1+y2= b 2xy1+y2= sinb2xy = sinb+y2sinbdifferentiating wrt x , we get 2y+2xdydx= 0+sinb×2ydydx2y = sinb×2ydydx-2xdydx2y = 2sinb×y-xdydxRegards

if sin-1​[ 2xy/1+y2​] =b,where b is a constant ,then what is the value of dy /dx? this question is in your study material topic test but i didn't understand how 2y = 2(y sin b - x) dy/dx come?

if sin^-1[ 2xy/1+y²] =b,where b is a constant ,then what is the value of dy /dx?
this question is in your study material topic test but i didn't understand how 2y = 2(y sin b - x) dy/dx come?