If sin-1x+sin-1y=2pi/3 then find the value of cos-1x+cos-1y
we know that
sin-1x = pi/2 - cos-1x
so sin-1x +sin-1y = 2pi/3
=> pi/2 - cos-1x + pi/2 - cos-1y= 2pi/3
=> pi - (cos-1x + cos-1y) = 2pi/3
=> (cos-1x + cos-1y) = pi-(2pi/3) = (3pi - 2pi)/3 = pi/3
so, cos-1x + cos-1y = pi/3
sin-1x = pi/2 - cos-1x
so sin-1x +sin-1y = 2pi/3
=> pi/2 - cos-1x + pi/2 - cos-1y= 2pi/3
=> pi - (cos-1x + cos-1y) = 2pi/3
=> (cos-1x + cos-1y) = pi-(2pi/3) = (3pi - 2pi)/3 = pi/3
so, cos-1x + cos-1y = pi/3