If sin theetha +cos theetha =2
Cosec theetha + sec theetha =???

Dear student
Given, sinθ+cosθ=2    ...(1)Squaring both sides, we getsinθ+cosθ2=22sin2θ+cos2θ+2sinθ cosθ=4    a+b2=a2+b2+2ab1+2sinθ cosθ=4    sin2A+cos2A=12sinθ cosθ=3sinθ cosθ=32      ....(2)Consider,cosecθ+secθ=1sinθ+1cosθ=cosθ+sinθsinθ cosθ=232    using 1 and 2=43So, cosecθ+secθ=43
Regards

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Dear student,

Sin A cos A = 2,
Cosec A sec A =?
Ans. Cosec A ? sec A = 1/sinA ?1/ cos A = 1/ Sin A Cos A = 1/2.

(You can replace theeta by A).
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