if sinA +sin B + sinC = 3 then
find the value of cosA + cosB +cosc...
Hi Shahbaz!
Here is the answer to your query.
–1 ≤ sin A ≤ 1, –1 ≤ sin B ≤ 1, –1 ≤ sinC ≤ 1
∴ (– 1) + (– 1) + (– 1) ≤ sin A + sin B + sin C ≤ 1 + 1 + 1
⇒ – 3 ≤ sin A + sin B + sin C ≤ 3
Given that sin A + sin B + sin C = 3
For this each sin A, sin B, sin C should each be 1
i.e. sin A = 1, sin B = 1, and sin C = 1
Similarly, cos B = 0 and cos C = 0
∴ cos A + cos B + cos C = 0
Hope! You got the answer.
Cheers!