If sum of Interior Angles of a polygon is 3¹/₂ its sum of Exterior angles ,then what is the shape of the polygon. Justify

Please Hurry I have test Tom.

let the number of sides of polygon be n.

sum of interior angles = (n-2)*180

sum of exterior angles =360 deg

sum of interior angles = 3 1/2  (=(3*2+1)/2=7/2)of sum of exterior angles

thus the polygon has 9 sides .and the polygon is nonagon.

hope this helps you.

cheers!!