If the discriminant of 3x2+2x+a=0 is double the discriminant of x2-4x+2=0, then value of a is :

(a) +2 (b) -2 (c) 1 (d) -1

if the discriminant of 3x2+2x+a=0is doudle the discriminant of x2-x+2=0,then find the value of a.
 

In the first equation , 3x²+2x+a=0
(a=3,  b=2,c=a)
D=b²- 4ac
   =(2)²-4*3*a
   =4-12a
In the second equation, x²-4x+2=0
(a=1,  b=-4,c=2)
D=b²- 4ac
   =(-4)²-4*1*2
   =16-8
   =8
It is given that discriminant of ​3x²+2x+a=0 = double discriminant of ​x²-4x+2=0.
So, 4-12a=(2)8
    4 -12a=16
     -12a=16-4
    -12a=12
       a=-12/12
   Therefore, a=-1.
 

-1 is the correct answer

explain it

The ans. Is -1 Explanation: D1= 4-12a D2= 8 So.. (4-12a)=2(8) Thus the ans. Would be -1. Hope this helps!

answer is -1/3