If the discriminant of 3x2+2x+a=0 is double the discriminant of x2-4x+2=0, then value of a is :
(a) +2 (b) -2 (c) 1 (d) -1

ans:(d)-1

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i need the explanation also

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if the discriminant of 3x2+2x+a=0is doudle the discriminant of x2-x+2=0,then find the value of a.
 
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In the first equation , 3x2+2x+a=0
(a=3,  b=2,c=a)
D=b2- 4ac
   =(2)2-4*3*a
   =4-12a
In the second equation, x2-4x+2=0
(a=1,  b=-4,c=2)
D=b2- 4ac
   =(-4)2-4*1*2
   =16-8
   =8
It is given that discriminant of ​3x2+2x+a=0 = double discriminant of ​x2-4x+2=0.
So, 4-12a=(2)8
    4 -12a=16
     -12a=16-4
    -12a=12
       a=-12/12
   Therefore, a=-1.
 
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-1 is the correct answer
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explain it
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The ans. Is -1 Explanation: D1= 4-12a D2= 8 So.. (4-12a)=2(8) Thus the ans. Would be -1. Hope this helps!
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answer is -1/3
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See the attached file. The answer is in it.

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