If the equation a - 5 x 2 + 2 a - 10 x + a + 10 = 0 has roots of the opposite sign, then (A) a > 10 (B) –15 < a < 5 (C) –10 < a < 5 (D) none of these Share with your friends Share 5 Brijendra Pal answered this Hi, If equation ax2+bx+c=0 has roots of opposite sign then product of zeroes= negativeso ca<0 Here a+10a-5<0 on number line -∞<+++++-10------5++++++>∞so a ∈-10,5 option C 11 View Full Answer