if the line x=y=z intersect the line sinAx+sinBy+sinCz=2d², sin2Ax+sin2By+sin2Cz=d², then sin(A/2)sin(B/2)sin(C/2) is equal to(where A+B+C=π)
(A)1/16 (B)1/8 (C)1/32 (D)1/12
Please explain step by step

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Anshika Maheshwari answered this

The following question can be solved as

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Question

if the line x=y=z intersect the line
sinAx+sinBy+sinCz=2d2,
sin2Ax+sin2By+sin2Cz=d2, then sin(A/2)sin(B/2)sin(C/2)
is equal to(where A+B+C=​π)
(A)1/16 (B)1/8 (C)1/32 (D)1/12
Please explain step by step

Anshika Maheshwari · Answer

The following question can be solved as
<img src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_5badb1dc389b7%20jpeg">

if the line x=y=z intersect the line sinAx+sinBy+sinCz=2d2, sin2Ax+sin2By+sin2Cz=d2, then sin(A/2)sin(B/2)sin(C/2) is equal to(where A+B+C=​π)(A)1/16 (B)1/8 (C)1/32 (D)1/12Please explain step by step

if the line x=y=z intersect the line sinAx+sinBy+sinCz=2d², sin2Ax+sin2By+sin2Cz=d², then sin(A/2)sin(B/2)sin(C/2) is equal to(where A+B+C=π)
(A)1/16 (B)1/8 (C)1/32 (D)1/12
Please explain step by step