If The Momentum Is Increased By 50% Then Kinetic Energy changes by

Let us consider a body of mass ‘m’ be moving with velocity ‘v’.

The momentum of the body is, p = mv

The kinetic energy of the body is, E = ½ mv2

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Kinetic Energy = 1/2 * m * v * v

mv = Momentum

If momentum is increased by 50% then Momentum is 3mv / 2

Kinetic Energy now = 1/2 * 3mv / 2 * v = 3mv2 / 4

Percentage increase in kinetic energy = ( 3mv2 / 4 - 1mv2 / 2 ) / (1mv2 / 2) * 100

= ( mv2 / 4 ) / ( (1mv2 / 2) * 100

= 1/2 * 100

= 50%

Ans: 50%

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