if the ordinates of the point on the parabola Y2=4ax axis twice the latus rectum prove that the abscissa of this point is twice the ordinate





Equation of the parabola,y2=4ax     .....1Let the point on the parabola be x1, y1.Given: ordinate=2×4a          The length of the latus ractum is 4a y1=8aTherefore, point x1, y1 becomes x1, 8a.Putting the values x1, 8a in 1, we get8a2=4ax164a2=4ax1x1=16ax1=2×8ax1=2×y1Hence, the abscissa of point P is twice the ordinate.

 

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We know that the latus rectum of a parabola  y2 = 4ax  ...(1)  is given by 4a . Let the required point be (x , y) So by the given condition that ordinate of a point is twice the latus  rectum , we mean that
y = 2 x 4a = 8a.  ......(2)
This point satisfies (1) .
So we get (8a)2 = 4ax where x is the abscissa of the point . 
we get 64a2 = 4ax or 16a = x
x = 16 a = 2 x 8a = 2 x ordinate ( using (2) ).
Hence proved  . Hope that helps.
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