If the polynomial x19 + x17 ​ + x13 + x11 + x7 + x5 + x3 is divided by x2 + 1, find the remainder.
(And please it is a request that do not send a link because i have seen all of them and none of them was helpful)

Dear Student,

Please find below the solution to the asked query:

We find value of x19 + x17 + x13 + x11 + x7 + x5 + x3x2 + 1 by long division method , As :


So, We write remainder :  x17  + x13  + x7 + x  - xx2 + 1


Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards

  • 2
Here, p (x) = x19 + x17 + x13 + x11 + x7 + x5 + x3 
          g (x) = x2 + 1
Equating g (x) to zero, we get, 
     g (x) = 0
=> x2 + 1 = 0
=> x2 = (–1)
=> x = root (–1)
Here, root of (-1) is not possible as it is an imaginary root. 
Thus it is not possible to get an imaginary remiander.

Kindly check your question again. 
  • -12
What are you looking for?