if the sum of the 20th terms of G.P. is 244 times of sum of 10th term of G.P. then find the common ratio ?...plz answer

sorry i couldn't understand this........

let t20=244t10

now t20=ar^19&t10=ar^9.

S₂₀=244*S₁₀

a(r²⁰-1)r-1=244 [a(r¹⁰-1)r-1

a & r-1 cancelled out

NOW,

  r²⁰-1= 244(r¹⁰-1)

  =244r¹⁰-244 ............(1)

let r¹⁰ =x, then r²⁰=(r¹⁰)²=x²

from (1) ,  x²-1=244x - 244

  x²- 244x + 243 = 0

after solving r¹⁰ = x =1  ,  r¹⁰ = x = 243

neglecting r¹⁰ = 243  as it is in decimal & also very small 

so, r¹⁰ = 1 , r = 1

  hope it helps

but it is given in the book as wrong answer

S20=244*S10

(r^20-1)=244(r^10-1)

r^20-1/r^10-1=244

take r^10=x,then r^20==x^2

1-x^2/1-x=244

(1+x) (1-x)/1-x=244

1+x=244

x=244

r^10=244

r^1o=3^5

so r=root3