if the system of equations 6x+2y=3 and kx+y=2 has a unique solution, find the value of k Share with your friends Share 0 Gursheen Kaur answered this Dear Student,Solution)The given equations are6x+2y-3=0..(i)kx+y-2=0...(ii)Here a1=6,b1=2,c1=-3 and a2=k,b2=1,c2=-2For the system , to have unique solution, we get, a1a2≠b1b2⇒6k≠21⇒k≠3Regards! 3 View Full Answer @#@#@#@#@# 🔛 answered this About this fully not conform -1 @#@#@#@#@# 🔛 answered this Sahi hai????? -1