If the vertical angle of a triangle is 130 degrees then the angle between the bisecting of the base angles of the triangle is?


We have,ABC is a triangle in which BAC=130°Now,ABC+BCA+BAC=180°ABC+BCA+130°=180°ABC+BCA=50°      .....1Now,OBC+OCB+BOC=180°OBC+OCB=180°-BOC2OBC+OCB=2180°-BOC2OBC+2OCB=2180°-BOCABC+BCA=360°-2BOC                        OB and OC are bisector of ABC and BCA respectively50°=360°-2BOC      From 12BOC=360°-50°2BOC=310°BOC=155°

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