If the vertical angle of a triangle is 130 degrees then the angle between the bisecting of the base angles of the triangle is? Share with your friends Share 0 Ashwini Kumar answered this We have,ABC is a triangle in which ∠BAC=130°Now,∠ABC+∠BCA+∠BAC=180°⇒∠ABC+∠BCA+130°=180°⇒∠ABC+∠BCA=50° .....1Now,∠OBC+∠OCB+∠BOC=180°⇒∠OBC+∠OCB=180°-∠BOC⇒2∠OBC+∠OCB=2180°-∠BOC⇒2∠OBC+2∠OCB=2180°-∠BOC⇒∠ABC+∠BCA=360°-2∠BOC ∵OB and OC are bisector of ∠ABC and ∠BCA respectively⇒50°=360°-2∠BOC From 1⇒2∠BOC=360°-50°⇒2∠BOC=310°∴∠BOC=155° 1 View Full Answer