# if there is a probability in getting tails in a single toss i.e. 1/2 then what is the probability of getting 2 tails in two tosses ? explain. if answer is 1/4 then explain how.

Please find below the solution to the asked query:

We know : Probability P ( E ) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{desired}\mathrm{events}\mathrm{n}(\mathrm{E})}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{events}\mathrm{n}(\mathrm{S})}$

When a coin toss there is only two possibilities = { H } , { T } , So

n ( S ) = 2

And

n ( E ) = 1 for T , So

Getting tails in single toss = $\frac{\mathbf{1}}{\mathbf{2}}$

And if coin tossed twice then total number of possibilities = { H , H } , { H , T }, { T , H } and { T , T } , So

n ( S ) = 4

And

n ( E ) = 1 for { T , T } , So

Getting 2 tails in two tosses = $\frac{\mathbf{1}}{\mathbf{4}}$

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