If three resistors of 6ohm,9ohm and 21ohm are connected in series to a 12V battery, find the total resistance of the circuit, find the current flowing through the circuit, find the potential difference across the 21ohm resister

In seri
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In series total resistance Req = 9 +21+6 =36 ohm now current V=IR so 12 = I ?36 so I is 1/3 ampere now potential across 21ohm is V = 1/3 ? 21= 7volt
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6+9+21=36ohm=R
and v=12v
then I=v/R
I=12/36=1/3
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