If triangle ABC is isosceles with AB=AC and C(O,r) is the incircle of the triangle ABC touching BC at L ,prove that L bisects BC
ΔABC is an isosceles triangle. C(O, r) is the incircle of ΔABC touching BC at I.
C(O, r) is the incircle of ΔABC.
∴ O is the point of intersection of angle bisector of ΔABC.
I.e., OB bisects ∠B and OC bisects ∠C.
In ΔABC,
AB = AC (Given)
∴ ∠C = ∠B (Equal sides have equal angles opposite to them)
⇒ ∠OCI = ∠OBI (OB bisects ∠B and OC bisects ∠C)
InΔOBI and ΔOCI,
∠OIB = ∠OIC (Radius is perpendicular to the tangent at point of contact)
∠OBI = ∠OCI (Proved)
OI = OI (Common)
∴ ΔOBI ΔOCI (AAS concurrence criterion)
⇒ BI = IC (CPCT)
Thus, I bisects the side BC.