Login

Class-12-science»Maths

if two collinear vectorsa and b are such that a=2i-4j+6k and mod b=root14 then b can be

a 2i-4j+6k b i-2j+3k c i+2j-3k d i+2j+3k e i-2j-3k

$\vec{a} = 2 \hat{i} - 4 \hat{j} + 6 \hat{k} \vec{b} = k \hat{i} + m \hat{j} + n \hat{k} \frac{2}{k} = \frac{- 4}{m} = \frac{6}{n} \Rightarrow \frac{1}{k} = \frac{- 2}{m} = \frac{3}{n} | | \vec{b} | = \sqrt{k^{2} + m^{2} + n^{2}} = \sqrt{14} T h e r e f o r e, o u t o f t h e g i v e n v e c t o r s \vec{b} c a n b e \hat{i} - 2 \hat{j} + 3 \hat{k}$

0

View Full Answer

Copyright © 2024 Aakash EduTech Pvt. Ltd. All rights reserved.

Aakash EduTech Pvt. Ltd.

What are you looking for?