If two tangents inclined at an angle of 60 are drawn to circle of radius 13cm , then length of each tangent is equal to:
Let PA and PB be two tangents to a circle with centre O and radius 13 cm.
We are given ∠APB = 60°
We know that two tangents drawn to a circle from an external point are equally inclined to the segment joining the centre to the point.
∴ ∠APO = ∠BPO = × ∠APB = × 60° = 30°
Also, OA ⊥ AP and OB ⊥ BP (radius ⊥ tangent at point of contact)
In right ΔOAP,
∴ PA = PB = (Lengths of tangents drawn from an external point to the circle are equal)