If x = a cos3θand y = a sin3θ, then find the value ofdy/dx at.x=∏/6 please explain also. Share with your friends Share 2 Manbar Singh answered this We have,x = a cos3θ⇒dxdθ = 3a cos2θ- sinθ = - 3a cos2θ sinθand y = a sin3θ⇒dydθ = 3a sin2θ cosθnow, dydx= dydθ ×dθdx = 3a sin2θ cosθ- 3a cos2θ sinθ = - tanθdydxθ = π6 = - tan π6 = - 13 1 View Full Answer Pranshul Joshi answered this The answer is 1/3 1/2. since dx/dt = -3acos2xsinx and dy/dt = 3asin2xcosx , so dy/dx becomes tan t, which at pi/6 is 1/3 1/2 0
