If x sin ( A + y) + sinA cos (A + y) = 0, prove that dy/dx = [ sin²(a + y) ] / sin a.

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If x sin ( A + y) + sinA cos (A + y) = 0, prove that dy/dx = [
sin2 (a + y) ] / sin a

Anuradha Sharma · Accepted Answer

We have    x sinA+y + sin A 
 cosA + y = 0⇒x = - sin A ×  cosA + y sinA + y⇒x = - sin A 
 cot A+yDifferentiating both sides with respect to y, we get⇒dxdy = - sin A × -cosec2A+y⇒dxdy = sin A × cosec2A+y⇒dxdy = sin Asin2A+y⇒dydx = sin2A+ysin A

If x sin ( A + y) + sinA cos (A + y) = 0, prove that dy/dx = [ sin2 (a + y) ] / sin a.

If x sin ( A + y) + sinA cos (A + y) = 0, prove that dy/dx = [ sin²(a + y) ] / sin a.