If x^myⁿ= (x+y)^m+nprove thatdy/dx=y/x?

Given thatx^myⁿ= (x+y)^m+n

⇒log (x^myⁿ) = log (x+y)^m+n⇒logx^m+ logyⁿ= (m+n) log (x+y)⇒mlogx+nlogy= (m+n) log (x+y)Differentiating both sides with respect tox