if z+√2|z+1|+i=0 and z=x+iythenA)x=-2B)x=2C)y=-2D)y=1 Share with your friends Share 13 Anuradha Sharma answered this z+2z+1+i=0x+iy+2x+1+iy+i = 0x+2x+12+y2+iy+1=0+i0Npw comparing the real and imaginary part we get, x+2x+12+y2=0....1or y+1=0 ⇒ y = -1Putting this value in equation 1 we get, x +2x+12+1=0x = -2x+12+1Squaring we get, x2=2x+12+2x2=2x2+4x+2+2x2+4x+4=0x+22=0x +2=0x = -2 67 View Full Answer
