ifsin-12a/1+a2- cos-11-b2/1+b2 = tan-12x/1-x2 then prove that x = a-b/1+ab.

sin-12a1+a2 - cos-11-b21+b2 = tan-12x1-x2Put a = tan θ; b = tan α  and  x = tan βNow, sin-12 tan θ1 + tan2θ - cos-11-tan2α1+tan2α = tan-12tan β1-tan2βsin-1sin 2θ - cos-1cos 2α = tan-1tan 2β2θ - 2α = 2βθ - α = βtan-1a - tan-1b = tan-1xtan-1a - b1 + ab= tan-1xa-b1+ab = x

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