In a circuit 3 capacitors are connected in series across points X and Y if no capacitor can sustain more - Physics -

Question

In a circuit 3 capacitors are connected in series across points X
and Y if no capacitor can sustain more than 50V then maximum
potential difference across X and Y is
C1=20 microfarad
C2= 40 microfarad
C3= 50 microfarad

Sushant · Accepted Answer

'Dear
student,

Please find below the solution to the asked query:

Let the charge on each capacitor be q
thus the potential  against each capacitor will be (q is in micro coulomb)across C1 capacitor = q/20 Vacross C2 capacitor  =q/40 Vacross C3 capacitor = q/50 Vas we can see for same charge on each capacitor as they are connected in series , the capacitor  C1has maximum potential drop, which according to the situation can be 50Vso q/20 = 50so q = 1000 micro coulombso the potential drop against C2 capacitor = 1000/40 = 25 voltswhile the potential drop against C3 capacitor will be 1000/50 = 20 voltshence as all the capacitors are in series so the potential difference across X and Y = 50 +25 +20 = 95volts

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In a circuit 3 capacitors are connected in series across points X and Y if no capacitor can sustain more than 50V then maximum potential difference across X and Y is C1=20 microfarad C2= 40 microfarad C3= 50 microfarad

In a circuit 3 capacitors are connected in series across points X and Y if no capacitor can sustain more than 50V then maximum potential difference across X and Y is
C1=20 microfarad
C2= 40 microfarad
C3= 50 microfarad