in a circuit there is a battery of 10v and a resistor of 5ohm which is connected in series with two resistors of 10 ohm each that are connected parallely. Find 'I' and 'V' across each resistor.
first calculate net resistance i.e. 50 ohm+1/(1/10+1/10)
then use V=IR
Inet=0.19 A (approx.)
in series current remains constant and V diifers
thus resister of 50 ohm will recieve 0.19A current.
using V=IR, V=50*0.19=9.5V
therefore the resisters in parallel will recieve 10-9.5=0.5V
in parallel, current differs but V remains constant
thus both 10 ohm resisters will recieve 0.5V voltage
using I=V/R in 1 10 ohm resistor
since both resistors in parallel have same resistance, both will have 0.5V and 0.05A
THEREFORE in R1, I=0.19A,V=9.5V
in R2, I=0.05A, v=0.5V
in R3, I=0.05A, v=0.5V