In a city it was found that the amount of daily deposit of pollutant is 3.2*10-5 g/sq cm. If the city has an area of 400 sq km and the pollutant is distributed evenly, find the amount of pollutant that falls on the city.

i) In a day

ii) In a year

the amount of daily deposit of pollutant = 3.2*10-5 g/sq cm=3.2*10-5*104=3.2*10-1 g/sq m
the area of the city = 400 sq km =400*103*103 =400*106 sq m

therefore the amount of pollutant that falls on the city in a day 3.2*10-1*400*106=1280*105=1.28*108 gm=1.28*105 kg

the amount of pollutant that falls on the city in a year = 1.28*105*365=467.2*105=4.672*107 kg

hope this helps you

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