In a collection of H- atoms, all the electrons jump from n = 5 to ground level finally (directly or indirectly), without emitting any line in Balmer series. The number of possible different radiation is?
With solution

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So transitions to Balmer series are not allowed. 
Thus the available transitions are : 5$\to$4, 5$\to$ 3, 5$\to$1 ; 4$\to$3, 4$\to$1; 3$\to$1

So the total transitions are = 6

However if the restriction of Balmer series was not mentioned , we can calculate the total no.of spectral lines using the formula: N = $\frac{n(n-1)}{2}, where n=5$
So , N = $\frac{5(5-1)}{2}= 10 lines$


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