In a container, two mole of a diatomic ideal gas is allowed to expand against 1 atm pressure and volume change from 2 L to 5 L. Calculate the change in Internal Energy. Share with your friends Share 20 Vartika Jain answered this Dear Student, w=P∆V=nR∆TTherefore, ∆T=P∆VnR=(1 atm)(5L-2L)2 mol×0.0821 Latmmol-1K-1=18.27 KNow, ∆U = nCV∆T For diatomic gas, CV=52R∆U =2 mol×52×8.314 JK-1mol-1×18.27 K=760 J 60 View Full Answer Siddharth Rathore answered this @Nishi, what are the units? The answer is 760 J by the way. I seek the process, not the direct answer :| 16