In a container, two mole of a diatomic ideal gas is allowed to expand against 1 atm pressure and volume change from 2 L to 5 L. Calculate the change in Internal Energy.

Dear Student,

w=PV=nRTTherefore, T=PVnR=(1 atm)(5L-2L)2 mol×0.0821 Latmmol-1K-1=18.27 KNow, U = nCVT  For diatomic gas, CV=52RU =2 mol×52×8.314 JK-1mol-1×18.27 K=760 J

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@Nishi, what are the units? The answer is 760 J by the way. I seek the process, not the direct answer :|
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