In a discharge tube, there are only two hydrogen atoms. If the electrons in both atoms are de-exciting from 4th orbit, the minimum and maximum number of spectral lines should respectively be
(A) 1. 4 (B) 4. 1 (C) 3. 4 (D) 1. 6
When the electrons of both the atoms are deexciting ie. shifting from 4th orbit to the ground orbit, the will emit some spectral lines.
The minimum lines will be emitted when there is only one spectral line from 4th to 1st orbit(ground orbit).
Same will be for the second H atom.
Thus,there is only one line and not two because both are same ie.from 4th orbit to the 1st one.
however, the maximum lines will be emitted from one H atom when it shows 3 spectral lines ie. from 4th to 3rd.3rd to 2nd.2nd to 1st.
If we take the same arrangement for the second atom,then we will have 3 lines in total as the lines will be same as the first one only.
however,if we take a diierent arrangement for the secong H atom ie.4th to 2nd and then from 2nd to 1st.
we will get 2 spectral lines but one of them will be different from the first h atom .the line from 4th to 2nd.
hence in total we will have 4 maximum lines for the two atoms.
MINIMUM LINES : 1
MAXIMUM LINES : 4
MAXIMUM LINES: 4