. In a double slit experiment, the distance between the slits is 3 mm and the slits are 2 m
away from the screen. Two interference patterns can be seen on the screen one due to
light with wavelength 480 nm, and the other due to light with wavelength 600 nm.
What is the separation on the screen between the fifth order bright fringes of the two
interference patterns?
Given:
distance between slits = d = 3 * 10-3 m
distance between slit and screen = D = 2 m
wavelength of wave 1 = l 1 = 480 * 10-9 m
wavelength of wave 2 = l 2 = 600 * 10-9 m
fifth order bright fringe = position of fifth maxima = x = n * l * d / D
for wave 1:
x 1 = 5 * 480 * 10-9 * 3 * 10-3 / 2 = 3600 * 10-12 m
for wave 2 :
x 2 = 5 * 600 * 10-9 * 3 * 10-3 / 2 = 4500 * 10-12 m
seperation on the screen between these two bright fringes = x2 - x1
= 4500 * 10-12 - 3600 * 10-12
= 900 * 10-12 m
= 900 picometers.
Hope the answer is right and it helps : D
distance between slits = d = 3 * 10-3 m
distance between slit and screen = D = 2 m
wavelength of wave 1 = l 1 = 480 * 10-9 m
wavelength of wave 2 = l 2 = 600 * 10-9 m
fifth order bright fringe = position of fifth maxima = x = n * l * d / D
for wave 1:
x 1 = 5 * 480 * 10-9 * 3 * 10-3 / 2 = 3600 * 10-12 m
for wave 2 :
x 2 = 5 * 600 * 10-9 * 3 * 10-3 / 2 = 4500 * 10-12 m
seperation on the screen between these two bright fringes = x2 - x1
= 4500 * 10-12 - 3600 * 10-12
= 900 * 10-12 m
= 900 picometers.
Hope the answer is right and it helps : D
