In a mixture of N2 and H2 in the ratio of 1:3 at 64 atm and 300 C, the percentage - Chemistry - Chemical and Ionic Equilibrium

Question

In a mixture of N2 and H2 in the ratio of 1:3 at 64 atm and 300 C,
the percentage of ammonia under equilibrium is 33 33 by volume
Calculate the equilibrium constant of the reaction using the
equation N2+3H2 2NH3

Gaurav Singh · Accepted Answer

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In a mixture of N2 and H2 in the ratio of 1:3 at 64 atm and 300 C, the percentage of ammonia under equilibrium is 33.33 by volume . Calculate the equilibrium constant of the reaction using the equation N2+3H2 2NH3