In a shotput event an athlete throws the shotput of mass 10 kgwith an initial speed of 1 m s - Science - Work and Energy

Question

In a shotput event an athlete throws the shotput of mass 10 kgwith
an initial speed of 1 m s –1 at 45° from a height 1 5 m
aboveground Assuming air resistance to be negligible and
accelerationdue to gravity to be 10 m s –2 , the kinetic
energy of the shotput when it just reaches the ground will be

Zafar · Accepted Answer

As there is no air friction and only gravitational force is acting
on the shotput the mechanical energy ( potential energy + kinetic
energy ) remain conserve

INITIAL MECHANICAL ENERGY = KINETIC ENERGY ONLY + POTENTIAL
ENERGY
= 12mv2+ mgh=12x10x1 + 10x10x1
5= 5 + 150=155 joulethis initial mechanical energy will be equal to the final mechanical energyhence the kinetic energy of the shotput when it hit the ground is 155 joule as the potential energy at the ground is zero