in a  triangle ABC ANGLE A +ANGLEB =65 ,ANGLEB +C=140 FIND A B C?

First we, excide the line BC to point D.

By exterior angle angle property angle A + angle B=  angle ACD=65,

It is given that angle A + angle B=65, Angle  B+ angle ACB=140.

then, by linear pair angle ACB+ angle ACD=180,

angle ACB=180-65=115,

now we have angle ACB=115,as it is given that angle ACB+ angle B=140,angle B=140-115=25,

we also knew that angle A+angle B=65,than

angle A+ angle B=65,= angle A+25=65,

so, angle A =65-25=40.

SO, angle A=40,

angle B=25,

angle ACB=115.