In a triangle PQR, PQ=12cm, PR=13cm and is having right angle at Q. Calculate Tan P - Cot R Share with your friends Share 3 Manbar Singh answered this In ∆PQR, PR2 = PQ2 + QR2 Pythagoras Theorem⇒QR2 = 132 - 122 = 169 - 144 = 25⇒QR = 5 cm tan P = perpendicularbase = QRPQ = 512cot R = baseperpendicular = QRPQ = 512so, tan P - cot R = 512 -512 = 0 2 View Full Answer