In case of N(SiH3)3, why do we see back bonding? How does Si has empty d orbitals when it is hybridized to Sp3 hybridization? shouldn't it just have covalency for 4 electrons
Dear Student,
Nitrogen has lone pair (N atom is sp2 hybridised) and silicon has 2 d orbital so the lone pair of Nitrogen makes bond with empty d orbital of silicon therefore back bonding happens Silicon belongs to the group carbon . Silicon belongs to 3rd period so it will have a d orbital but it combines with only three hydrogen so hydrogen occupies only P orbital and not d-orbital which is vacant. Empty d orbital of Si orbital forming dπ-pπ back bonding.
Regards,
Nitrogen has lone pair (N atom is sp2 hybridised) and silicon has 2 d orbital so the lone pair of Nitrogen makes bond with empty d orbital of silicon therefore back bonding happens Silicon belongs to the group carbon . Silicon belongs to 3rd period so it will have a d orbital but it combines with only three hydrogen so hydrogen occupies only P orbital and not d-orbital which is vacant. Empty d orbital of Si orbital forming dπ-pπ back bonding.
Regards,