In figure X, Y are the mid points of sides AB and CD of a parallelogram. ABCD. AY and DX are joined intersecting at P, CX and By are joined intersecting at Q. Show that PXQY is a parallelogram.
Let us observe the following figure.
Since X is the midpoint, AX = XB, Y is the midpoint, CY = YD.
ABCD is a parallelo gram, therefore, AB = CD.
Therefore, AX = CY
Also, AB is parallel to DC.
Therefore, AX is parallel to CY
Thus, AXCY is a parallelogram.
Consequently, PY is parallel to QX.
Since X is the midpoint, AX = XB, Y is the midpoint, CY = YD.
ABCD is a parallelo gram, therefore, AB = CD.
Therefore, BX = DY
Also, AB is parallel to DC.
Therefore, BX is parallel to DY
Thus, BXDY is a parallelogram.
Consequently, PX is parallel to QY.
Thus, the arguments are,
1. PY is parallel to QX
2. PX is parallel to QY
Therefore, PXQY is a parallelogram