In H2S2O7, what are the oxidation numbers of oxygen?
The solution is as follows:
In H2S2O7 oxidation number of:
H = +1
S = +6
O = x
2(+1) + 2 (+6) + 7(x) = 0
2 + 12 + 7x = 0
14 + 7x = 0
7x = -14
x = -2
In H2S2O7 oxidation number of:
H = +1
S = +6
O = x
2(+1) + 2 (+6) + 7(x) = 0
2 + 12 + 7x = 0
14 + 7x = 0
7x = -14
x = -2