In how many ways,we can choose two teams of mixed double for a tennis tournament from four couples such that if any couple participates,then it is in same team.

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Please find below the solution to the asked query:

$$\begin{gathered} \mathrm{As} \mathrm{there} \mathrm{are} 4 \mathrm{couples} \mathrm{and} \mathrm{each} \mathrm{couple} \mathrm{is} \mathrm{always} \mathrm{in} \mathrm{the} \mathrm{same} \mathrm{team}. \\ \mathrm{Hence} \\ \mathrm{Number} \mathrm{of} \mathrm{selections}{=}^4{\mathrm{C}}_2=\frac{4\times 3}{2\times 1}=\mathbf{6}\mathbf{ }\left(\mathbf{Answer}\right) \end{gathered}$$

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