in RD Sharma pg 10.52 question 6 (iv) is false. please explain. fast pls. Share with your friends Share 0 Manbar Singh answered this The given statement is , If the altitude from one vertex of a ∆ bisects opposite side, then∆ may be isosceles.The above statement is false, as we know that, If the altitude from one vertex of a ∆ bisects opposite side, then ∆ is always isosceles.Here is the proof.Consider a ∆ ABC, in which AD⊥BC and also AD bisects BC. In ∆ADB and ∆ADC AD = AD common∠ADB = ∠ADC 90° each BD = DC as AD bisects BC⇒∆ADB ≅∆ADC SAS⇒AB = AC CPCT⇒∆ABC is an isosceles ∆ Hope this would have cleared your doubt. -2 View Full Answer