in the above vedio they have drawn 2 circles to form the perpendicular bisector of the line segment

we can directely draw 2 acs

one on the upper side while the other lower side at both the points isin't it?

Here is the answer to your question.
You can draw the arcs of equal radii (more than half of PQ) considering P and Q as center such that the one pair of arcs must intersect above PQ and other pair of remaining arcs must intersect below PQ as follows.
Best wishes!

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