Arun Ev , asked a question
Subject: Physics , asked on 16/2/11

In the circuit -' TO COMPARE THE EMF OF TWO CELLS USING POTENTIOMETER ' . suppose the battery is connected to ' A ' end of potentiometer , let a null deflection be obtained in galvanometer at point ' J ' . . at that state why the emf of cell becomes equal to the potential difference between the points ' A ' and ' J ' ?

ramanan423... , added an answer, on 19/6/11

how TO COMPARE THE EMF OF TWO CELLS USING POTENTIOMETER

  • Was this answer helpful?
  • 0
View Full Answer

What are you looking for?

Syllabus