in the figure , AD is the bisector of angle BAC.Prove that AB > BD. Share with your friends Share 3 Manbar Singh answered this In ∆ABC, since AD bisects ∠BAC, then∠BAD = ∠CAD ....1Now, we know that exterior angle of a ∆ is greater than each of its interior opposite angle.So, ∠ADB > ∠CAD⇒∠ADB >∠BAD using 1In ∆ABD,∠ADB >∠BAD⇒AB > BD Sides opposite to greater angle is longer 15 View Full Answer None answered this angle D = 90 angle B is less than 90 therefore opposite sides AB is greater AD 1