In the figure, find the four angles A, B, C, D in the parallelogram ABCD.

4a + 5a + 6a = 180o (angle sum property of triangle)
15a = ​180o
a = 12
4a = 4 x 12 = 48
5a = 5 x 12 = 60
6a = 6 x 12 = 72
angle B = angle D (opposite sides of parallelogram)
72o = ​angle D
angle D + angle A = 180o (adjacent angles of parallelogram )
72 + ​angle A​ = 180o
angle A = 108o
angle A = angle C
108o = ​angle C
Therefore,
Angle A = 108o
Angle B = 72o
Angle C = 108o
Angle D = 72o

 

  • 7
dont know
  • -1
dont know
 
  • -1
A = 108, B = 72, C = 108 and D = 72
  • 2
Very easy 
  • -1
nilotpal answer is right
  • -1
good answer diy
  • -1
108,72,108,72
  • 3
angle a=108
angle b=72
angle c=108
angle d=72
  • 1
It is so easy..
  • -2
What are you looking for?