In the given figure ABCD is parallelogram in which DC=10cm and BC=4root3cm. AP is perpendicular to DC. If angle ADC = 60. Find:
(i) length of AP
(ii) Area of parallelogram ABCD


ABCD is a parallelogram and opposite sides of parallelogram are equal, AB=CD= 10 cmAnd BC=AD=43 cmIn right angled triangle APD,sin D=APADsin60°=AP4332=AP43AP=6 cmArea of parallelogram ABCD=base × height = DC×AP=10×6=60 cm2

  • 3
What are you looking for?